Question

Друзья мне это предмет очень трудно, помогите пж Минус девять икс квадрат плюс восемь икс плюс один

Answer 1

$- 9 {x}^{2} + 8x + 1 = - 9(x - 1)(x + \frac{1}{9} )\\-----------------------------\\9 {x}^{2} - 8x - 1 = 0 \\ d1 = 16 + 9 = 25 \\ x1 = \frac{4 + 5}{9} = 1 \\ x2 = - \frac{1}{9}$

Answer 2

Solving the Equation

To solve the equation -9x^2 + 8x + 1, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

where a = -9, b = 8, and c = 1.

Applying the Quadratic Formula

Plugging the values into the quadratic formula:

x = (-8 ± √(8^2 - 4*(-9)*1)) / (2*(-9))

Calculating the Discriminant

The discriminant, b^2 - 4ac, determines the nature of the roots. If the discriminant is positive, there are two distinct real roots. If it's zero, there is one real root. If it's negative, there are two complex roots.

Discriminant = 8^2 - 4*(-9)*1 = 64 + 36 = 100

Calculating the Roots

Using the quadratic formula:

x = (-8 + √100) / (-18) = (-8 + 10) / (-18) = 2 / (-18) = -1/9

x = (-8 - √100) / (-18) = (-8 - 10) / (-18) = -18 / (-18) = 1

So, the solutions to the equation -9x^2 + 8x + 1 are x = -1/9 and x = 1.