Question

ПОМОЖЕТЕ СРОЧНО ОЧЕНЬ ПОЖ 1) 9х^2-100=0 2) (4y-3)^2-(2y+5)^2=0 ХОТЬ ЧТО ТО ПЖ (

Answer 1

X^2 = 100/9
x = +- 10/3

16y^2 - 24y + 9 - 4y^2 - 20y + 25 = 0
12y^2 - 44y + 34 = 0
k = -22
D1 = 484 - 408 = 76
y = (22 +- корень(76))/12

насчет последнего сомневаюсь

Answer 2

1) To solve the equation 9x^2 - 100 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 9, b = 0, and c = -100. Plugging these values into the quadratic formula, we get:

x = (0 ± √(0^2 - 4 * 9 * -100)) / (2 * 9)

Simplifying further:

x = ± √(3600) / 18

x = ± 60 / 18

Therefore, the solutions to the equation 9x^2 - 100 = 0 are x = 10/3 and x = -10/3.

2) To solve the equation (4y - 3)^2 - (2y + 5)^2 = 0, we can simplify the equation and then factor it.

Expanding the equation, we get:

(4y - 3)^2 - (2y + 5)^2 = 0 (16y^2 - 24y + 9) - (4y^2 + 20y + 25) = 0 16y^2 - 24y + 9 - 4y^2 - 20y - 25 = 0 12y^2 - 44y - 16 = 0

Now, we can factor the quadratic equation:

12y^2 - 44y - 16 = 0 4(3y^2 - 11y - 4) = 0

To factor the expression 3y^2 - 11y - 4, we need to find two numbers whose product is -12 and whose sum is -11. These numbers are -12 and 1. Therefore, we can rewrite the equation as:

4(3y + 1)(y - 4) = 0

Setting each factor equal to zero, we get:

3y + 1 = 0 or y - 4 = 0

Solving for y in each equation:

3y = -1 or y = 4

y = -1/3 or y = 4

Therefore, the solutions to the equation (4y - 3)^2 - (2y + 5)^2 = 0 are y = -1/3 and y = 4.

I hope this helps! Let me know if you have any further questions.