Лодка плыла течению 4 часа, а затем 5 часов против течения, пройдя всего 115 км. Найдите
собственную скорость лодки, если известно, что скорость течения реки равна 2 км/ч.Ответы на вопрос
4(х+2)+5(х-2)=115
4х+8+5х-10=115
9х=117
х=13; значит скорость лодки 13 км/ч
Ответ: 13км/ч
Problem Analysis
We are given that a boat traveled with the current for 4 hours and then against the current for 5 hours, covering a total distance of 115 km. The speed of the current is given as 2 km/h. We need to find the speed of the boat.Solution
Let's assume the speed of the boat in still water is x km/h.When the boat is traveling with the current, its effective speed is the sum of its speed in still water and the speed of the current. So, the effective speed is (x + 2) km/h.
When the boat is traveling against the current, its effective speed is the difference between its speed in still water and the speed of the current. So, the effective speed is (x - 2) km/h.
We can use the formula distance = speed × time to calculate the distances traveled in each case.
The distance traveled with the current for 4 hours is (x + 2) × 4 km.
The distance traveled against the current for 5 hours is (x - 2) × 5 km.
According to the problem, the total distance traveled is 115 km. So, we can set up the equation:
(x + 2) × 4 + (x - 2) × 5 = 115
Simplifying the equation:
4x + 8 + 5x - 10 = 115
9x - 2 = 115
9x = 117
x = 13
Therefore, the speed of the boat in still water is 13 km/h.
Answer
The speed of the boat in still water is 13 km/h.Топ вопросов за вчера в категории Алгебра
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