Question

Решите пожалуйста " способ группировки" bc + 3ac — 2ab — 6a²

Answer 1

bc + 3ac — 2ab — 6a²=
c(b+3)-2a(b+3a)=
(c-2a)*(b+3a)

Answer 2

Solving the Expression "3ac - 2ab - 6a²"

To solve the expression "3ac - 2ab - 6a²," we can use the method of grouping. This involves rearranging the terms in a way that allows us to factor out common factors.

First, let's factor out the common terms from the given expression.

Step 1: Factor Out Common Terms We start by factoring out the common terms from the expression "3ac - 2ab - 6a²."

We can factor out the common factor "a" from each term: ``` 3ac - 2ab - 6a² = a(3c - 2b - 6a) ```

Now, the expression has been factored to "a(3c - 2b - 6a)."

Step 2: Grouping Next, we can use the method of grouping to further factor the expression. This involves grouping the terms in a way that allows us to factor out common factors from each group.

We can group the terms as follows: ``` 3c - 2b - 6a = (3c) - (2b + 6a) ```

Now, we have two groups: (3c) and (2b + 6a).

Step 3: Factor Out Common Factors from Each Group We can factor out the common factor from the second group: ``` 2b + 6a = 2(b + 3a) ```

Now, the expression "3c - 2b - 6a" has been factored into two groups: (3c) and (2(b + 3a)).

Step 4: Final Expression Putting it all together, the factored form of the expression "3ac - 2ab - 6a²" using the method of grouping is: ``` 3ac - 2ab - 6a² = a(3c - 2b - 6a) = a(3c - 2(b + 3a)) ```

This is the factored form of the given expression using the method of grouping.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.