Question

Дана арифметическая прогрессия 128 ; -64 ; 32… найдите 10й член этой прогрессии

Answer 1

Найдем разность -64-128 равно -192. а10 равно а1+9d равно 128+9*(-192) равно -1600

Answer 2

Finding the 10th Term of an Arithmetic Progression

To find the 10th term of the given arithmetic progression, we can use the formula for the nth term of an arithmetic progression:

nth term (An) = a + (n - 1)d

Where: - a is the first term - n is the term number - d is the common difference

Given the arithmetic progression: 128, -64, 32, ...

We can identify: - a (the first term) = 128 - d (the common difference) = -64 - 128 = -192

Now, we can use the formula to find the 10th term: 10th term (A10) = 128 + (10 - 1)(-192)

Calculating: A10 = 128 + 9(-192) A10 = 128 - 1728 A10 = -1600

Therefore, the 10th term of the given arithmetic progression is -1600.