Question

Постройте график линейной функции y=2x-3 и укажите с его помощью абсциссу точки графика с ординатой -7 пожалуйста помогите решить буду благодарен !:)))))

Answer 1

y=2x-3

при у=-7

-7=2х-3

2х=-7+3

Х=-2

для точки с ординатой (-7) абсцисса (-2 )

Answer 2

Graph of the Linear Function y = 2x - 3

To plot the graph of the linear function y = 2x - 3, we can use the formula y = mx + c, where m is the slope and c is the y-intercept.

The slope of the function y = 2x - 3 is 2, and the y-intercept is -3. This means that for every unit increase in x, y will increase by 2 units, and the graph will intersect the y-axis at the point (0, -3).

Let's plot the graph to visualize it.

import matplotlib.pyplot as plt
import numpy as np

x = np.linspace(-5, 5, 100)  # Generate 100 x-values from -5 to 5
y = 2*x - 3  # Calculate the corresponding y-values

plt.plot(x, y, '-r', label='y=2x-3')  # Plot the graph
plt.plot(0, -3, 'bo')  # Mark the y-intercept
plt.xlabel('x')
plt.ylabel('y')
plt.title('Graph of y=2x-3')
plt.axhline(0, color='black',linewidth=0.5)
plt.axvline(0, color='black',linewidth=0.5)
plt.grid(color = 'gray', linestyle = '--', linewidth = 0.5)
plt.legend(loc='upper left')
plt.show()

The graph of the linear function y = 2x - 3 is a straight line with a slope of 2 and a y-intercept of -3.

Finding the Abscissa for y = -7

To find the abscissa (x-coordinate) for the point on the graph where the ordinate (y-coordinate) is -7, we can use the equation y = 2x - 3 and solve for x when y = -7.

Substitute y = -7 into the equation y = 2x - 3: -2x = -7 + 3 -2x = -4 x = -4 / -2 x = 2

So, the abscissa for the point on the graph with the ordinate -7 is x = 2.

Therefore, the point on the graph of y = 2x - 3 with the ordinate -7 has the abscissa 2.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask!