Question

Выполнить действия (2i+3)+4i(1-i)

Answer 1

2i+3+4i-4i^2=6i+3-4i^2=-2i(2i+3)+3

Answer 2

I can chat with you in Russian and help you with various tasks. To perform the operations, we need to use the rules of complex arithmetic. First, we distribute the 4i to the parentheses:

(2i + 3) + 4i(1 - i) = (2i + 3) + 4i - 4i^2

Then, we simplify the i^2 term, which is equal to -1:

(2i + 3) + 4i - 4i^2 = (2i + 3) + 4i + 4

Next, we combine the like terms:

(2i + 3) + 4i + 4 = 7 + 6i

Therefore, the final answer is:

$$7 + 6i$$Ответь+подробно.+Выполнить+действия+(2i+3)+4i(1-i)