Question

В треуггольннике авсд ас=вс,угол с равен 52 градус . Найдите внешний угол свд . Овет дайте в градусах

Answer 1

Решение:
ВС=АС следовательно треугольник АВС - равнобедренный. следовательно
угол В = углу А (углы при основании равноб. треуг.)
угол А + угол В+ угол С = 180 градусов (сумма углов треуг.)
уг. А + уг. В + 52 градуса = 180 градусов
уг.А + уг. В = 128 градусов.
уг. А=уг. В =128 градусов : 2 =  64 градуса
угол В + угол ДВС = 180 градусов (смежные)
угло ДВС = 180-64 = 116 градусов.
Ответ: 116 градусов.

Answer 2

Угол С=52
(180-52):2=64 угол А= углу В( так как треугольник равнобедренный
угол СВД=180-угол СВА=180-64=116

Answer 3

Problem Analysis

We are given a triangle ABC, where AB = AC and angle C is equal to 52 degrees. We need to find the external angle SVD.

Solution

To find the external angle SVD, we can use the fact that the sum of the measures of the angles of a triangle is always 180 degrees.

Since angle C is 52 degrees, we can find angle A using the fact that the sum of the measures of angles A and C is equal to 180 degrees. Therefore, angle A is equal to 180 - 52 = 128 degrees.

Now, we can find angle B using the fact that the sum of the measures of angles A and B is equal to 180 degrees. Therefore, angle B is equal to 180 - 128 = 52 degrees.

Since angle B is equal to angle C, triangle ABC is an isosceles triangle. This means that sides AB and AC are equal in length.

Now, we can find the external angle SVD. The external angle SVD is equal to the sum of angles A and B. Therefore, the external angle SVD is equal to 128 + 52 = 180 degrees.

Answer

The external angle SVD is 180 degrees.

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