Question

(x-4)(y+5);(5а-7)(3а+1);(5у^2-1)(3у^2-1 );(7у-1)(у^2-5у+1);3b(b-2)(2+4b) сделайте пожалуйста срочно надо

Answer 1

(x-4)(y+5)=xy+5x-4y-20
(5а-7)(3а+1)=15a²-21a+5a-7=15a²-16a-7

(5у^2-1)(3у^2-1 )=15y^4-3y^2-5y^2+1=15y^4-8y^2+1

(7у-1)(у^2-5у+1)=7y^3-y^2-35y^2+5y+7y-1=7y^3-36y^2+12y-1

3b(b-2)(2+4b) =3b(2b-4+4b²-8b)=3b(4b²-6b-4)=12b³-18b²-12b

Answer 2

Simplifying Expressions:

Let's simplify the given expressions one by one:

1. (x-4)(y+5): To simplify this expression, we can use the distributive property of multiplication over addition. We multiply each term in the first expression by each term in the second expression and then combine like terms, if any.

Expanding the expression: (x-4)(y+5) = x(y+5) - 4(y+5)

Now, let's simplify each term: x(y+5) = xy + 5x -4(y+5) = -4y - 20

Combining the simplified terms: (x-4)(y+5) = xy + 5x - 4y - 20

2. (5a-7)(3a+1): Using the same method as above, we can simplify this expression.

Expanding the expression: (5a-7)(3a+1) = 5a(3a+1) - 7(3a+1)

Simplifying each term: 5a(3a+1) = 15a^2 + 5a -7(3a+1) = -21a - 7

Combining the simplified terms: (5a-7)(3a+1) = 15a^2 + 5a - 21a - 7

3. (5y^2-1)(3y^2-1): Expanding the expression: (5y^2-1)(3y^2-1) = 5y^2(3y^2-1) - 1(3y^2-1)

Simplifying each term: 5y^2(3y^2-1) = 15y^4 - 5y^2 -1(3y^2-1) = -3y^2 + 1

Combining the simplified terms: (5y^2-1)(3y^2-1) = 15y^4 - 5y^2 - 3y^2 + 1

4. (7y-1)(y^2-5y+1): Expanding the expression: (7y-1)(y^2-5y+1) = 7y(y^2-5y+1) - 1(y^2-5y+1)

Simplifying each term: 7y(y^2-5y+1) = 7y^3 - 35y^2 + 7y -1(y^2-5y+1) = -y^2 + 5y - 1

Combining the simplified terms: (7y-1)(y^2-5y+1) = 7y^3 - 35y^2 + 7y - y^2 + 5y - 1

5. 3b(b-2)(2+4b): Expanding the expression: 3b(b-2)(2+4b) = 3b(b^2 - 2b)(2+4b)

Simplifying each term: 3b(b^2 - 2b) = 3b^3 - 6b^2 (2+4b) = 2 + 4b

Combining the simplified terms: 3b(b-2)(2+4b) = (3b^3 - 6b^2)(2 + 4b)

Please let me know if you need further assistance or if you have any other questions!