Question

Найти наименьшее значение функции: Ответ:

Answer 1

$f(x)=2 x^{2} -3x+5 \\ f'(x)=4x-3 \\ 4x-3=0 \\ 4x=3 \\ x= \frac{3}{4} \\ f( \frac{3}{4})=2* (\frac{3}{4} )^{2} -3* \frac{3}{4} +5=2* \frac{9}{16} - \frac{9}{4} +5= \frac{9}{8} - \frac{9}{4} +5= \\ =1.125-2.25+5=-1.125+5=3.875 \\ 3.875=3 \frac{875}{1000} =3 \frac{7}{8}$

Answer 2

Производная: 4х-3. Приравняем к 0
4х-3=0
х=3/4
Теперь х  подставим в функцию
f(3/4)= 2* (9/16) - 3*(3/4) +5= 18/16-9/4 + 5 = 1.125-2.25+5=3.875  (просто я дроби не очень люблю поэтому перевела)

Answer 3

Finding the Minimum Value of a Function

To find the minimum value of a function, we need to analyze the given function and determine the lowest point on its graph. Unfortunately, the search results provided do not contain a specific function or equation to analyze. Without the function itself, it is not possible to provide a detailed answer.

If you can provide the specific function or equation you would like to find the minimum value for, I would be happy to assist you further.