Question

решить уравнение2(5x-7)(1+x)=0решить систему уравнений

Answer 1

10х-14*1+х=0 11х-14=0 11х=14 х=14/11 х=1,3/11

Answer 2

Solving the Equation 2(5x-7)(1+x)=0

To solve the equation 2(5x-7)(1+x)=0, we can use the zero product property, which states that if the product of two or more factors is equal to zero, then at least one of the factors must be zero. Let's solve it step by step.

First, we expand the equation: 2(5x-7)(1+x)=0

Expanding gives us: 10x - 14 + 2x - 14x^2 + 10x - 14 = 0

Combining like terms: -14x^2 + 22x - 28 = 0

Now, we have a quadratic equation in the form ax^2 + bx + c = 0, where a = -14, b = 22, and c = -28. We can use the quadratic formula to solve for x: x = (-b ± √(b^2 - 4ac)) / (2a)

Let's calculate the discriminant (b^2 - 4ac) to determine the nature of the roots.

The discriminant is given by: Δ = b^2 - 4ac

Substituting the values: Δ = 22^2 - 4*(-14)*(-28) Δ = 484 - 1568 Δ = -1084

Since the discriminant is negative, the equation has no real roots. Therefore, the solutions for the given equation are complex numbers.

Solving the System of Equations

The system of equations is not clearly defined in the provided search results. If you have a specific system of equations in mind, please provide the equations, and I'd be happy to help you solve them.