Question

Tg t * cos (- t) + sin (π + t).

Answer 1

tg t * cos (- t) + sin (π + t)=(sin t)*(cos t) /  cos t  - sin t =sin t - sin t = 0

Answer 2

Sure, I'd be happy to help with that. It looks like you've provided an expression involving trigonometric functions. Let's break it down step by step.

The expression you've given is:

Tg(t) * cos(-t) + sin(π + t)

First, let's clarify that "Tg" is typically used to represent the tangent function, so I'll interpret "Tg" as "tan" throughout the explanation.

Calculating the Expression Step by Step:

1. cos(-t): The cosine function is an even function, so cos(-t) = cos(t).

2. sin(π + t): Using the angle addition identity for sine, sin(π + t) = sin(π) * cos(t) + cos(π) * sin(t). Since sin(π) = 0 and cos(π) = -1, this simplifies to 0 * cos(t) + (-1) * sin(t) = -sin(t).

3. tan(t): This term remains as tan(t).

So, the expression becomes:

tan(t) * cos(t) - sin(t)

This is the detailed breakdown of the given expression. If you have any more specific questions about this or anything else, feel free to ask!