Question

В коробке лежат 36 фломастеров, из них 10 фломастеров — фиолетовые, 6 фломастеров — голубые, а остальные — желтые. Какова вероятность того, что наугад взятый фломастер не будет ни фиолетовым, ни голубым? Ответ детально объясните

Answer 1

Сказано, найти вероятность того, что не будет фиолетового и голубого фломастеров, но есть желтые. Значит, будем искать вероятность выпадения желтых карандашей. Найдем их количество:
36 - (10+6) = 20 (шт)
Найдем вероятность = 5/9, т.к. 20/36 = 5/9
Ответ: 5/9

Answer 2

Calculating the Probability of Drawing a Non-Purple or Non-Blue Marker

To calculate the probability of drawing a marker that is neither purple nor blue, we can use the following approach:

1. Total Number of Markers: - There are 36 markers in total.

2. Number of Purple Markers: - There are 10 purple markers.

3. Number of Blue Markers: - There are 6 blue markers.

4. Number of Yellow Markers: - The remaining markers are yellow.

Probability Calculation

To calculate the probability, we can use the following formula: \[ P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]

Applying the Formula

The probability of drawing a marker that is neither purple nor blue can be calculated as follows:

\[ P(\text{non-purple and non-blue marker}) = \frac{\text{Number of yellow markers}}{\text{Total number of markers}} \]

\[ P(\text{non-purple and non-blue marker}) = \frac{36 - (10 + 6)}{36} \]

\[ P(\text{non-purple and non-blue marker}) = \frac{36 - 16}{36} \]

\[ P(\text{non-purple and non-blue marker}) = \frac{20}{36} \]

\[ P(\text{non-purple and non-blue marker}) = 0.5556 \]

So, the probability of drawing a marker that is neither purple nor blue is 0.5556 or approximately 55.56%.