Question

Три бригады рабочих изготовили за смену 100 деталей . Вторая бригада изготовила на 5 деталей больше, чем первая бригада, и на 15 деталей больше, чем третья . Сколько деталей изготовила каждая бригада

Answer 1

Хд-2 бригада х-5д-1 бригада х-15д-3 бригада х+х-5+х-15=100 3х=120 х=40д-2 40-5=35д-1 40-15=25д-3

Answer 2

Problem Analysis

We are given that three brigades of workers produced a total of 100 parts in one shift. The second brigade produced 5 more parts than the first brigade and 15 more parts than the third brigade. We need to determine how many parts each brigade produced.

Solution

Let's assume the number of parts produced by the first brigade is x.

According to the given information: - The second brigade produced 5 more parts than the first brigade, so the number of parts produced by the second brigade is x + 5. - The second brigade also produced 15 more parts than the third brigade, so the number of parts produced by the third brigade is (x + 5) - 15.

The total number of parts produced by all three brigades is 100. Therefore, we can write the equation:

x + (x + 5) + ((x + 5) - 15) = 100

Simplifying the equation: 3x - 5 = 100

Solving for x: 3x = 105 x = 35

So, the first brigade produced 35 parts, the second brigade produced 35 + 5 = 40 parts, and the third brigade produced (35 + 5) - 15 = 25 parts.

Answer

The first brigade produced 35 parts, the second brigade produced 40 parts, and the third brigade produced 25 parts.