Question

(4-b)(b+4)=b(во2ой)-16-(b-1)(3-4b)=(1-b)(4b-3)(b+1)(3-2b)=3+b-2b(во2ой)(b-4)во2ой=b(во2ой)-8b+16

Answer 1

$(4-b)(b+4)=16-b^2$
$-(b-1)(3-4b)=(1-b)(3-4b)=3-7b+4b^2$
$(b+1)(3-2b)=3+b-2b^2$
$(b-4)^2=b^2-8b+16$

Answer 2

Simplifying and Solving the Equations

To solve the equations, let's simplify each expression step by step.

Equation 1: (4-b)(b+4) = b^2 - 16

Expanding the left side of the equation:

(4 - b)(b + 4) = 4(b) + 4(-b) + b(b) + b(4) = 4b - 4b + b^2 + 4b = b^2 + 4b + 4b = b^2 + 8b

So, the equation becomes:

b^2 + 8b = b^2 - 16

Subtracting b^2 from both sides:

8b = -16

Dividing both sides by 8:

b = -2

Equation 2: (b - 1)(3 - 4b) = 1 - b(4b - 3)

Expanding the left side of the equation:

(b - 1)(3 - 4b) = b(3) - b(4b) - 1(3) + 1(4b) = 3b - 4b^2 - 3 + 4b = -4b^2 + 7b - 3

Expanding the right side of the equation:

1 - b(4b - 3) = 1 - 4b^2 + 3b

So, the equation becomes:

-4b^2 + 7b - 3 = 1 - 4b^2 + 3b

Simplifying:

7b - 3 = 1 + 3b

Subtracting 3b from both sides:

4b - 3 = 1

Adding 3 to both sides:

4b = 4

Dividing both sides by 4:

b = 1

Equation 3: (1 - b)(4b - 3)(b + 1)(3 - 2b) = 3 + b - 2b^2(b - 4)^2

Expanding the left side of the equation:

(1 - b)(4b - 3)(b + 1)(3 - 2b) = (1 - b)(4b - 3)(3 - 2b)(b + 1)

Expanding each term:

(1 - b)(4b - 3) = 4b - 4b^2 - 3 + 3b = -4b^2 + 7b - 3

(3 - 2b)(b + 1) = 3(b) + 3(1) - 2b(b) - 2b(1) = 3b + 3 - 2b^2 - 2b

So, the equation becomes:

(-4b^2 + 7b - 3)(3b + 3 - 2b^2 - 2b) = 3 + b - 2b^2(b - 4)^2

Expanding both sides:

(-4b^2 + 7b - 3)(3b + 3 - 2b^2 - 2b) = (-2b^2 + 3b - 1)(3 + b - 2b^2)(3 + b - 2b^2)

Simplifying:

-12b^3 + 21b^2 - 9b + 12b^2 - 21b + 9 - 8b^3 + 12b^2 - 4b - 8b^2 + 12b - 4 = 3 + b - 2b^2(b - 4)^2

Combining like terms:

-20b^3 + 37b^2 - 22b + 5 = 3 + b - 2b^2(b - 4)^2

To solve this equation, we need more information about the value of b(во2ой) and b(во2ой)(b - 4)во2ой.

Please provide the values of b(во2ой) and b(во2ой)(b - 4)во2ой so we can continue solving the equation.