Question

С двух станций, расстояние между которыми равно 360 км, одновременно вышли навстречу друг другу два поезда. скорость одного из них на 10 км\ч. меньше скорости другого. найдите скорость каждого поезда, если они встретились через 2,4 ч. после начала движения

Answer 1

х- скорость 1-го поезда

х+1т - скорость 2-го поезда

(х+х+10)*2,4=360

2х+10=150

2х=140

х=70

70 км/ч - скорость первого поезда.

70+10= 80

80 км/ч - скорость 2-го поезда.

Answer 2

Problem Analysis

We have two trains that start simultaneously from two stations and travel towards each other. The distance between the stations is 360 km. The speed of one train is 10 km/h less than the speed of the other train. We need to find the speed of each train given that they meet after 2.4 hours.

Solution

Let's assume the speed of the slower train is x km/h. Therefore, the speed of the faster train will be x + 10 km/h.

We can use the formula speed = distance / time to find the speeds of the trains.

The slower train covers a distance of 360 km in 2.4 hours, so its speed is 360 / 2.4 = 150 km/h.

The faster train has a speed that is 10 km/h more than the slower train, so its speed is 150 + 10 = 160 km/h.

Therefore, the speed of the slower train is 150 km/h and the speed of the faster train is 160 km/h.

Answer

The speed of the slower train is 150 km/h and the speed of the faster train is 160 km/h.