Question

Из пункта А в пункт В со скоростью 60 км/ч выехал мотоциклист. Через 30 мин навстречу ему из В выехал другой мотоциклист, скорость которого составляла 50 км/ч. Какое время ехал второй мотоциклист до встречи с первым, если расстояние между А и В равно 162 км?

Answer 1

30 минут = 0,5 часа
1) 60 * 0,5 = 30 км - проехал первый до выезда второго
2) 162 - 30 = 132 км - оставшееся расстояние
3) 60 + 50 = 110 км/ч - общая скорость
4) 132 : 110 = 1,2 часа - ехали до момента встречи встречи.
Ответ: второй мотоциклист ехал 1,2 часа до встречи с первым.

Answer 2

Problem Analysis

We are given that a motorcyclist travels from point A to point B at a speed of 60 km/h. After 30 minutes, another motorcyclist starts from point B and travels towards point A at a speed of 50 km/h. We need to find the time it takes for the second motorcyclist to meet the first motorcyclist, given that the distance between points A and B is 162 km.

Solution

Let's calculate the time it takes for the first motorcyclist to reach the meeting point. Since the speed is given in km/h and the time is given in minutes, we need to convert the time to hours.

The first motorcyclist travels at a speed of 60 km/h and the time is 30 minutes, which is equivalent to 0.5 hours. Therefore, the distance traveled by the first motorcyclist is:

Distance = Speed × Time = 60 km/h × 0.5 h = 30 km

Now, let's calculate the remaining distance between the meeting point and point B:

Remaining Distance = Total Distance - Distance Traveled by First Motorcyclist = 162 km - 30 km = 132 km

The second motorcyclist travels at a speed of 50 km/h. We can use the formula:

Time = Distance / Speed

to calculate the time it takes for the second motorcyclist to cover the remaining distance:

Time = Remaining Distance / Speed = 132 km / 50 km/h = 2.64 hours

Therefore, the second motorcyclist takes approximately 2.64 hours to meet the first motorcyclist.

Answer

The second motorcyclist takes approximately 2.64 hours to meet the first motorcyclist.