Question

Прошу вас помогите мне)) 7 класс...Запишите в виде дроби. 2а\51х^6y*17x^2y, 24b^2\3a^6:16bc\a^5

Answer 1

2a*17x²y/51x^6y=2a/3y^4
24b²*a^5/(3a^6*16bc)=b/2ac

Answer 2

Converting Expressions to Fractions

To convert the given expressions into fractions, we'll start by simplifying each expression separately.

Expression 1: 2a/51x^6y * 17x^2y

To simplify this expression, we can multiply the numerators together and the denominators together.

The numerator will be: 2a * 17x^2y = 34ax^2y

The denominator will be: 51x^6y

So, the expression can be written as: (34ax^2y) / 51x^6y

Expression 2: 24b^2/3a^6 : 16bc/a^5

To simplify this expression, we'll first convert the division to multiplication by taking the reciprocal of the second fraction.

So, the expression becomes: 24b^2/3a^6 * a^5/16bc

Now, we can multiply the numerators together and the denominators together.

The numerator will be: 24b^2 * a^5 = 24a^5b^2

The denominator will be: 3a^6 * 16bc = 48a^6bc

So, the expression can be written as: (24a^5b^2) / (48a^6bc)

Final Results

After simplifying the given expressions, they can be written in the form of fractions as:

1. (34ax^2y) / 51x^6y 2. (24a^5b^2) / (48a^6bc)