Question

(u+2) в кубе - u(u+4) Решите многочлен.

Answer 1

1) (u+2)в кубе = (u+2)(u+2)(u+2) = (u в кв.+4u+4)(u+2)=(u в кубе+2u в кв.+4u в кв.+8u+4u+8)= u в кубе+6u в кв.+12u+8

2)u в кубе+6u в кв.+12u+8 -u(u+4)= u в кубе+6u в кв.+12u+8 -u в кв.-4u=u в кубе+5u в кв.+8u+8

Answer 2

Solving the Polynomial Equation

To solve the given polynomial equation (u + 2) = u(u + 4), we can start by expanding the right-hand side and simplifying the equation.

Expanding the right-hand side: (u + 2) = u(u + 4) Expanding u(u + 4) gives us u^2 + 4u.

So, the equation becomes: u + 2 = u^2 + 4u

Now, let's rearrange the equation to set it to zero: u^2 + 3u - 2 = 0

Applying the Quadratic Formula

We can solve this quadratic equation using the quadratic formula, which is given by: x = (-b ± √(b^2 - 4ac)) / (2a)

Where: - a = 1 - b = 3 - c = -2

Plugging these values into the quadratic formula: u = (-3 ± √(3^2 - 4*1*(-2))) / (2*1) u = (-3 ± √(9 + 8)) / 2 u = (-3 ± √17) / 2

So, the solutions for the equation (u + 2) = u(u + 4) are: u = (-3 + √17) / 2 and u = (-3 - √17) / 2.

Therefore, the solutions for the given polynomial equation are u = (-3 + √17) / 2 and u = (-3 - √17) / 2.