
Два автомоббиля отпровляются в 420 километровый пробег первый едет со скорость на 10 км больше
второго и прибывает к финишу на час раньше второго. найдите скорость автомобиля пришедшего к финишу вторым

Ответы на вопрос




Problem Analysis
We are given two cars that are traveling a distance of 420 kilometers. The first car is traveling at a speed that is 10 km/h faster than the second car. The first car arrives at the finish line one hour earlier than the second car. We need to find the speed of the second car.Solution
Let's assume the speed of the second car is x km/h. Since the first car is traveling 10 km/h faster, its speed would be x + 10 km/h.We can use the formula speed = distance / time to calculate the time taken by each car to complete the 420-kilometer distance.
For the first car: - Speed = x + 10 km/h - Distance = 420 km - Time = Distance / Speed = 420 / (x + 10) hours
For the second car: - Speed = x km/h - Distance = 420 km - Time = Distance / Speed = 420 / x hours
According to the problem, the first car arrives at the finish line one hour earlier than the second car. So, we can set up the following equation:
Time taken by the second car - Time taken by the first car = 1 hour
(420 / x) - (420 / (x + 10)) = 1
Now, let's solve this equation to find the value of x.
Calculation
To solve the equation (420 / x) - (420 / (x + 10)) = 1, we can multiply both sides of the equation by x(x + 10) to eliminate the denominators.(x(x + 10)) * (420 / x) - (x(x + 10)) * (420 / (x + 10)) = 1 * (x(x + 10))
420(x + 10) - 420x = x(x + 10)
420x + 4200 - 420x = x^2 + 10x
4200 = x^2 + 10x
x^2 + 10x - 4200 = 0
Now, we can solve this quadratic equation to find the value of x.
Using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = 10, and c = -4200.
x = (-10 ± √(10^2 - 4 * 1 * -4200)) / (2 * 1)
x = (-10 ± √(100 + 16800)) / 2
x = (-10 ± √16900) / 2
x = (-10 ± 130) / 2
x = (120 / 2) or (-140 / 2)
x = 60 or -70
Since speed cannot be negative, the speed of the second car is 60 km/h.
Answer
The speed of the car that arrived at the finish line second is 60 km/h.

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