Question

A2(a во второй степени)=а(x+2)-2

Answer 1

Смотри ответ на листочке

Answer 2

I can help you with your math problem. Here is the detailed solution:

To solve for $x$, we need to simplify the equation and isolate $x$ on one side. First, we can expand the expression $A^2(a^2)$ by using the formula $(a+b)^2=a^2+2ab+b^2$. We get:

$$A^2(a^2) = (a+x)^2 + 2(a+x)(-1) + (-1)^2$$

Next, we can simplify the equation by distributing the terms and combining the like terms. We get:

$$a^2 + 2ax + x^2 - 2a - 2x + 1 = ax + 2a - 2$$

Then, we can subtract $ax$ and $2a$ from both sides of the equation. We get:

$$x^2 + ax - 4a - 1 = 0$$

Finally, we can use the quadratic formula to find the value of $x$. The quadratic formula is:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

where $a$, $b$, and $c$ are the coefficients of the quadratic equation $ax^2 + bx + c = 0$. In our case, we have:

$$a = 1, b = a, c = -4a - 1$$

Plugging these values into the quadratic formula, we get:

$$x = \frac{-a \pm \sqrt{a^2 - 4(1)(-4a - 1)}}{2(1)}$$

Simplifying further, we get:

$$x = \frac{-a \pm \sqrt{17a^2 + 16}}{2}$$

This is the final answer. There are two possible values for $x$, depending on whether we choose the positive or negative sign in the formula.Ответь+подробно.+A2(a+во+второй+степени)=а(x+2)-2