Question

Решите уравнение

Answer 1

$||x^2-x|-x^2|=4 \\ \\ \\ 1)|x^2-x|-x^2=4 \\ 2)|x^2-x|-x^2=-4 \\ \\1)x^2-x-x^2=4,x^2-x \geq 0 \\ -(x^2-x)-x^2=4,x^2-x\ \textless \ 0 \\ x=-4 \\\\2)x^2-x-x^2=-4,x^2-x \geq 0 \\ -(x^2-x)-x^2=-4,x^2-x\ \textless \ 0 \\ x=4$

Ответ: x=-4,x=4