Question

Помогите пожалуйста с решением

Answer 1

$\left \{ {{ x^{2} -14x+13\ \textgreater \ 0} \atop { x^{2} -18x+45\ \textless \ 0}} \right.$

$\left \{ {{(x-13)(x-1)\ \textgreater \ 0} \atop {(x-15)(x-3)\ \textless \ 0}} \right.$

1)
      +                    -                         +
________₀___________₀______________
                1                     13
x ∈ (- ∞ ; 1)∪(13 ,+∞)
2)
      +                    -                           +
________₀____________₀______________
                3                       15
x ∈ ( 3 ; 15)
Окончательный ответ:
 \\\\\\\\\\\\\\\\\\\\                                         ///////////////////////////////////////////////
__________₀_________₀___________₀___________₀___________
                    1                 3                      13                   15
                                       |||||||||||||||||||||||||||||||||||||||||||||||||||||
x ∈ (13 ; 15)

2) $\left \{ {{ \frac{x-1}{2}*6- \frac{2x+3}{3}*6+ \frac{x}{6}*6\ \textless \ 2*6- \frac{x+5}{2}*6 } \atop {1*8- \frac{x-5}{8}*8+ \frac{4-x}{2}*8\ \textless \ 3x*8- \frac{x+1}{4}*8 }} \right.$

$\left \{ {{3x-3-4x-6+x\ \textless \ 12-3x-15} \atop {8-x-5+16-4x\ \textless \ 24x-2x-2}} \right.$

$\left \{ {{3x\ \textless \ 6} \atop {-27x\ \textless \ -21}} \right.$

$\left \{ {{x\ \textless \ 2} \atop {x\ \textgreater \ \frac{7}{9}}} \right.$
Ответ: x ∈ (7/9 , 2)