Question

Найдите x, заранее спасибо

Answer 1

$X^2= \frac{11*(|8-6|-11/2)^2}{4*5*7*8}= \frac{11*(-3,5)^2}{160*7}= \frac{11*49/4}{160*7}= \frac{11*7}{160*4} = \frac{77}{64*10}$
$X= \sqrt{ \frac{77}{64*10} } = \sqrt{ \frac{7,7}{64} } = \frac{ \sqrt{7,7} }{8}$

Answer 2

$x^{2} = \frac{11*(|2*4-2*3|- \frac{11}{2} )^2}{(2+2)*(2+3)*(3+4)*(2+4)}$
$x^{2} = \frac{11*(|8-6|- \frac{11}{2} )^2}{4*5*7*6}$
$x^{2} = \frac{11*(2- \frac{11}{2} )^2}{4*5*7*6}$
$x^{2} = \frac{11*(\frac{4-11}{2} )^2}{4*5*7*6}$
$x^{2} = \frac{11*(\frac{4-11}{2} )^2}{4*5*6*7}$
$x^{2} = \frac{11*\frac{7^2}{4} }{4*5*6*7}$
$x^{2} = \frac{11*7^2 }{4*4*5*6*7}$
$x^{2} = \frac{11*7^2 }{4^2*5*6*7}$
$x=б \sqrt{ \frac{11*7^2 }{4^2*5*6*7} }$
$x=б \sqrt{ \frac{11*7 }{4^2*5*6} }$
$x=б \sqrt{ \frac{77 }{4^2*30} }$
$x=б \frac{{1} }{4} \sqrt{ \frac{77}{30} }$