Question

Помогите с уравнением !!

Answer 1

$.....\frac{3}{(x-3)(x+3)}+\frac{1}{(x-3)^2}-\frac{3}{2x(x+3)}=0\quad OOF:\; x\ne \pm 3,x\ne 0\\\\3\cdot 2x(x-3)+2x(x+3)-3(x-3)^2=0\\\\5x^2+6x-27=0\\\\x_1=\frac{-3-12}{5}=-3\; \notin OOF,\; x_2=\frac{-3+12}{5}=\frac{9}{5}=1,8\\\\Otvet:x=1,8$

$ax^2+2px+c=0\\\\\frac{D}{4}=p^2-ac\\\\x_{1,2}=\frac{-p\pm \sqrt{\frac{D}{4}}}{a}$