Question

Упростить

Answer 1

$(a+3)( \frac{1}{2a-5}+ \frac{1}{a+5})* \frac{ a^{2}+5a }{9 a^{2}+3 a^{3}}+ \frac{2a-3}{2a-5}=(a+3)\frac{a+5+2a-5}{(2a-5)(a+5)}* \frac{a(a+5)}{3 a^{2}(3+a)}$$+ \frac{2a-3}{2a-5}= \frac{1}{2a-5}+ \frac{2a-3}{2a-5}= \frac{1+2a-3}{2a-5}= \frac{2(a-1)}{2a-5}$