Question

ПОМОГИТЕ! СРОЧНО! 238 под (б)

Answer 1

$f(x)=tg(x^2+ \frac{ \pi }{6} ) \\\ f'(x)= \cfrac{1}{\cos^2(x^2+ \frac{ \pi }{6} )} \cdot (x^2+ \frac{ \pi }{6} )'= \cfrac{2x}{\cos^2(x^2+ \frac{ \pi }{6} )} \\\ f'(x_0)= f'(0)= \cfrac{2\cdot0}{\cos^2(0^2+ \frac{ \pi }{6} )}=0$