Question

Решите пож* Срочно..

Answer 1

$\frac{5x+4}{2} +3= \frac{9x}{4} \\ \frac{5x+4}{2} + \frac{12}{4} - \frac{9x}{4} =0 \\ \frac{10x+8}{4} + \frac{12}{4} - \frac{9x}{4} =0 \\ \frac{10x+8+12-9x}{4} =0 \\ \frac{x+20}{4} =0 \\ x+20=0 \\ x=-20$