
Решение неравенства.Помогите пожалуйста решить неравенство и определить сколько целых решений оно
имеет на промежутке [-6; 6]. Заранее большое спасибо!9*(2x-7) < 2корня из 22*(2х-7)*Неужели так сложно, что никто не поможет?(((

Ответы на вопрос

(2x-7)(9-2√22)<0
2x-7>0,т.к 9-2√22<0
2x>7
x>3,5
x∈(3,5;6]
x=4;5;6- 3 решения



Solving the Inequality
To solve the given inequality, we will follow these steps:
1. Simplify the expression on the left-hand side of the inequality. 2. Solve the resulting equation. 3. Determine the number of integer solutions within the given interval.
Let's apply these steps to the given inequality:
9*(2x-7) < 2√(22*(2x-7))
Step 1: Simplify the expression on the left-hand side of the inequality.
To simplify the expression, we can start by dividing both sides of the inequality by √(22*(2x-7)):
(9*(2x-7))/(√(22*(2x-7))) < 2
Simplifying further, we can cancel out the common factor of (2x-7):
9/√(22) < 2
Step 2: Solve the resulting equation.
To solve the equation, we need to isolate x. Let's square both sides of the equation to eliminate the square root:
(9/√(22))^2 < 2^2
Simplifying further:
81/22 < 4
Step 3: Determine the number of integer solutions within the given interval.
To find the number of integer solutions within the interval [-6, 6], we need to check if any integer values of x satisfy the inequality.
Let's evaluate the inequality for x = -6, -5, -4, ..., 6:
For x = -6: 81/22 < 4 (True) For x = -5: 81/22 < 4 (True) For x = -4: 81/22 < 4 (True) For x = -3: 81/22 < 4 (True) For x = -2: 81/22 < 4 (True) For x = -1: 81/22 < 4 (True) For x = 0: 81/22 < 4 (True) For x = 1: 81/22 < 4 (True) For x = 2: 81/22 < 4 (True) For x = 3: 81/22 < 4 (True) For x = 4: 81/22 < 4 (True) For x = 5: 81/22 < 4 (True) For x = 6: 81/22 < 4 (True)
From the above evaluations, we can see that the inequality is true for all integer values of x within the interval [-6, 6]. Therefore, the inequality has an infinite number of integer solutions within the given interval.
I hope this helps! Let me know if you have any further questions.


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