Question

2x-4 / x³-8 Решите Тема сокращение алгебрических дробей!!!

Answer 1

2x-4 / x³-8=2(х-2)/(x-2)(x²+2x+4)=2/x²+2x+4

Answer 2

$\frac {2x-4}{x^3-8}=\frac {2(x-2)}{(x-2)(x^2+2x+4)}=\frac {2}{x^2+2x+4}$

Answer 3

Simplifying Algebraic Fractions

To simplify the expression 2x - 4 / x³ - 8, we can start by factoring the numerator and denominator.

The numerator, 2x - 4, can be factored out the common factor of 2:

2x - 4 = 2(x - 2)

The denominator, x³ - 8, is a difference of cubes and can be factored using the formula:

a³ - b³ = (a - b)(a² + ab + b²)

In this case, a = x and b = 2:

x³ - 8 = (x - 2)(x² + 2x + 4)

Now, we can rewrite the expression as:

(2(x - 2)) / ((x - 2)(x² + 2x + 4))

Next, we can cancel out the common factor of (x - 2) in the numerator and denominator:

2 / (x² + 2x + 4)

Therefore, the simplified form of the expression 2x - 4 / x³ - 8 is 2 / (x² + 2x + 4).

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