Question

Помогите с с1 задание во вложении

Answer 1

$6sin ^2x -5sin x-4=0\\6a^2-5a-4=0\\ a_1=4/3,a_2=-1/2\\sinx=-1/2\\ x=(-1)^{n+1}\pi/6+\pi n\\ x_1=7\pi/6+2\pi n\\x_2=11\pi/6+2\pi n\\ -\frac{17\pi}{6};-\frac{13\pi}{6}$