Question

Из пункта А в пункт B выехала грузовая машина. Спустя 1,2 ч. вслед за ней выехал автобус. Через 48 мин. после своего выезда он отставал от машины на 24 км.Найти скорость автобуса, если известно, что она больше скорости грузовика на 30 км\ч.

Answer 1

48/60=0,8

1,2х+0,8х=0,8(х+30)+24

1,2х=48

х=48/1,2

х=40км/ч - скорость грузовика

40+30=70км/ч - скорость автобуса

Answer 2

скорость автобуса=х

скорость грузовика х-30

1,2+0,8=2 ч время, за которое расстояние уменьшилось до 24 км

2(х-30)-0,8х=24

2х-60-0,8х=24

1,2х=24+60=84

х=84/1,2=70 км/ч скорость автобуса

Answer 3

Problem Analysis

We are given that a truck leaves point A and after 1.2 hours, a bus leaves point A as well. After 48 minutes from the bus's departure, it is 24 km behind the truck. We need to find the speed of the bus, knowing that it is 30 km/h faster than the speed of the truck.

Solution

Let's assume the speed of the truck is x km/h. Since the bus is 30 km/h faster, its speed will be x + 30 km/h.

We can use the formula distance = speed × time to solve this problem.

The truck travels for 1.2 hours, so the distance it covers is 1.2x km.

The bus travels for 48 minutes, which is 0.8 hours, so the distance it covers is 0.8(x + 30) km.

According to the problem, the bus is 24 km behind the truck. Therefore, we can set up the equation:

1.2x - 0.8(x + 30) = 24

Now, let's solve this equation to find the value of x.

1.2x - 0.8x - 24 = 24 0.4x = 48 x = 120

The speed of the truck is 120 km/h. Since the speed of the bus is 30 km/h faster, the speed of the bus is 120 + 30 = 150 km/h.

Therefore, the speed of the bus is 150 km/h.

Answer

The speed of the bus is 150 km/h.