Question

Составить график прямой. 2х-y+1=0

Answer 1

2х-y+1=0
у=2х+1
для построения прямой достаточно найти две точки и провести через них прямую

Answer 2

Graphing the Equation 2x - y + 1 = 0

To graph the equation 2x - y + 1 = 0, we can rewrite it in slope-intercept form, which is y = kx + b, where k is the slope and b is the y-intercept.

From the given equation, 2x - y + 1 = 0, we can isolate y to get y = 2x + 1.

Now we have the equation in slope-intercept form, where the slope (k) is 2 and the y-intercept (b) is 1.

To graph this equation, we can plot two points and draw a line through them. Let's choose two points:

Point 1: When x = 0, y = 2(0) + 1 = 1. So, the first point is (0, 1). Point 2: When x = 1, y = 2(1) + 1 = 3. So, the second point is (1, 3).

Now we can plot these points on a coordinate plane and draw a line through them.

The graph of the equation 2x - y + 1 = 0 is a straight line that passes through the points (0, 1) and (1, 3).

Here is the graph:


Please note that the graph is a visual representation of the equation and helps us understand the relationship between x and y values.