Question

Выполните умножение многочленов 1)(11-d)(d+11) 2)(4+b)(b-4). 3)(10+3d)(3d-10)

Answer 1

$(11-d)(d+11) = 121 - d {}^{2}$
$(4+b)(b-4) = b {}^{2} - 16$
$(10+3d)(3d-10) = 9d {}^{2} - 100$

Answer 2

Вот, думаю правильно

Answer 3

1) (11-d)(d+11) = 11d + 121 - d^2 - 11d = -d^2 + 121

2) (4+b)(b-4) = 4b - 16 + b^2 - 4b = b^2 - 16

3) (10+3d)(3d-10) = 30d - 100 + 9d^2 - 100 = 9d^2 + 30d - 200