Question

3(x+1)(x-1)=2(x-2)(x+2)+x^2+2x Помогите пожалуйста!!!

Answer 1

3(x+1)(x-1) = 2(x-2)(x+2)+x²+2x
3(x²-1) = 2(x²-4)+x²+2x
3x²-3 = 2x²-8+x²+2x
3x²-2x²-x²-2x = -8+3
-2x = -5
x = 2,5
Ответ : 2,5.

Answer 2

Solving the Equation

To solve the equation 3(x+1)(x-1) = 2(x-2)(x+2) + x^2 + 2x, we can follow these steps:

1. Expand both sides of the equation: - 3(x+1)(x-1) = 2(x-2)(x+2) + x^2 + 2x - 3(x^2 - 1) = 2(x^2 - 4) + x^2 + 2x

2. Simplify the equation: - 3x^2 - 3 = 2x^2 - 8 + x^2 + 2x - 3x^2 - 3 = 3x^2 + 2x - 8

3. Combine like terms: - 3x^2 - 3 = 3x^2 + 2x - 8 - 3x^2 - 3x^2 - 2x = -8 + 3

4. Simplify further: - -2x = -5

5. Divide both sides by -2 to solve for x: - x = -5 / -2 - x = 5/2

Therefore, the solution to the equation 3(x+1)(x-1) = 2(x-2)(x+2) + x^2 + 2x is x = 5/2.