Question

Поезд прошёл перегон за 2ч, а второй за 3ч.Всего за это время он прошёл расстояние 330км.Найдите скорость поезда на каждом перегоне, если на втором перегоне она была на 10км/ч больше,чем на первом... решите плз

Answer 1

На первом 66, на втором 76

Answer 2

Problem Analysis

We are given that a train traveled one distance in 2 hours and another distance in 3 hours, covering a total distance of 330 km. We need to find the speed of the train on each leg of the journey, knowing that the speed on the second leg was 10 km/h higher than on the first leg.

Solution

Let's assume the speed of the train on the first leg is x km/h. Since the train traveled for 2 hours on this leg, the distance covered can be calculated using the formula: distance = speed × time. Therefore, the distance covered on the first leg is 2x km.

Similarly, let's assume the speed of the train on the second leg is x + 10 km/h. Since the train traveled for 3 hours on this leg, the distance covered can be calculated as 3(x + 10) km.

According to the problem, the total distance covered is 330 km. Therefore, we can write the equation:

2x + 3(x + 10) = 330

Now, let's solve this equation to find the value of x.

Solving the Equation

Expanding the equation, we have:

2x + 3x + 30 = 330

Combining like terms, we get:

5x + 30 = 330

Subtracting 30 from both sides, we have:

5x = 300

Dividing both sides by 5, we get:

x = 60

Answer

The speed of the train on the first leg is 60 km/h. Since the speed on the second leg is 10 km/h higher, the speed on the second leg is 70 km/h.

Therefore, the train traveled at a speed of 60 km/h on the first leg and 70 km/h on the second leg.

Please let me know if I can help you with anything else.