Question

Скорость велосипедиста в 5 раз больше скорости пешехода.однажды они отправились одновременно навстречу друг другу из пунктов,расстояние между которыми 30 км .какой руть проедет велосипедист до встречи с пешеходом?

Answer 1

скорость пешехода -v

скорость велосепедиста - vх

 

время t прохождения пути до встречи одинаково так как они вышли одновременно

 

растоение пешехода - s, велосипедиста - 30-s

 

s=vt

t=s\v

 

s\v = 30-s  \  5v

5vs = 30v-st

6vs=30v

 s=5 (км) прошел пешеход

 

30-5=25 км - проехал велосипедист 

 

 

Answer 2

Problem Analysis

We are given that the speed of the cyclist is 5 times greater than the speed of the pedestrian. They start simultaneously from two points that are 30 km apart. We need to determine the distance the cyclist will travel before meeting the pedestrian.

Solution

Let's assume the speed of the pedestrian is x km/h. Since the speed of the cyclist is 5 times greater, the speed of the cyclist is 5x km/h.

To find the distance the cyclist will travel before meeting the pedestrian, we need to determine the time it takes for them to meet. We can use the formula:

Time = Distance / Speed

Let's denote the distance the cyclist travels as d km. The distance the pedestrian travels will be 30 - d km, as they are moving towards each other.

The time it takes for the cyclist to meet the pedestrian is the same for both of them. Therefore, we can set up the following equation:

Time taken by cyclist = Time taken by pedestrian

d / (5x) = (30 - d) / x

Simplifying the equation:

d = (5x * (30 - d)) / x

Solving for d:

d = (150x - 5xd) / x

dx + 5xd = 150x

6xd = 150x

d = 150x / 6x

d = 25

Therefore, the cyclist will travel 25 km before meeting the pedestrian.

Answer

The cyclist will travel 25 km before meeting the pedestrian.