Question

Решите неравенство 3х²+x+1>0 и еще √36-х2 помогите прошуу

Answer 1

3x²+x+1>0      3x²+x+1=0  D=(1-12)<0⇒корней нет и функция больше 0 при всех х∈(-∞,∞) 

во второй задаче √36-х² нет ясности - какое условие больше 0 или меньше, или еще что-то.

Answer 2

Solving the inequality 3x² + x + 1 > 0

To solve the inequality 3x² + x + 1 > 0, we need to find the values of x that make the expression greater than zero.

To do this, we can use the quadratic formula or factor the quadratic expression. Let's use the quadratic formula:

The quadratic formula states that for an equation of the form ax² + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / (2a)

In our case, a = 3, b = 1, and c = 1. Plugging these values into the quadratic formula, we get:

x = (-1 ± √(1² - 4 * 3 * 1)) / (2 * 3)

Simplifying further:

x = (-1 ± √(1 - 12)) / 6

x = (-1 ± √(-11)) / 6

Since the discriminant (b² - 4ac) is negative, the quadratic equation has no real solutions. Therefore, there are no values of x that satisfy the inequality 3x² + x + 1 > 0.

Evaluating √36 - x²

To evaluate the expression √36 - x², we substitute the value of x into the expression and simplify.

Since you haven't provided a specific value for x, we can't evaluate the expression further. Please provide a value for x so that we can help you with the calculation.

If you have any further questions, please let me know!