Question

В трёх баках всего было 70 л воды. В первом баке воды на 10 л больше, чем во втором. Когда из первого бака перелили в третий 24 л воды, во втором и третьем баках воды стало поровну. Сколько первоначально литров воды было в первом баке?

Answer 1

Во втором баке Х литров, В первом  Х+10.Когда из первого перелили в третий 24 литра, то в первом стало Х+10-24=Х-14 литров, а во втором и третьем по Х литров.
 В сумме (Х-14)+Х+Х=70, отсюда Х=28 л.
Ответ: первоначально в первом баке было 38 литров.

Answer 2

Problem Analysis

The problem describes a scenario with three tanks of water, where the total amount of water is 70 liters. The first tank has 10 liters more water than the second tank. When 24 liters of water are transferred from the first tank to the third tank, the second and third tanks have an equal amount of water.

Solution

Let's solve this step by step.

1. Let's assume the amount of water in the second tank is x liters. Then the amount of water in the first tank is (x + 10) liters. 2. After transferring 24 liters from the first tank to the third tank, the amount of water in the first tank becomes (x + 10 - 24) and the amount of water in the third tank becomes 24. 3. At this point, the amount of water in the second and third tanks is the same, so we can set up an equation to solve for x.

Calculation

Let's solve for x using the equation: (x + 10 - 24) = 24 Solving for x: (x - 14) = 24 x = 24 + 14 x = 38

Answer

So, the initial amount of water in the second tank (and therefore the total amount of water in the first tank) is 38 liters.

Note: The solution is based on the information provided and the calculations performed.