Question

Решите систему уравнений: 5x-3y=0 3x+4y=29

Answer 1

5x-3y=0
3x-4y=29

Умножим первое уравнение на (-3), второе на 5
-15х+9у=0
15х-20у=145

Складываем
-11у=145
у=-145/11=-13 целых 2/11

х=(29+4у)/3= (29+4·(-145/11))/3=(29·11-4·145)/33=-261/33=-87/11=-7целых 10/11
Ответ. (-7целых 10/11; -13 целых 2/11)

Answer 2

Ответ смотри на фото:

Answer 3

I can help you solve systems of linear equations. There are different methods to do that, such as graphing, substitution, elimination, and matrix operations.

For your system of equations, I will use the elimination method. This method involves adding or subtracting the equations to eliminate one of the variables. Here are the steps:

1. Multiply the first equation by 4 and the second equation by 3 to make the coefficients of y equal. This gives:

20x - 12y = 0 9x + 12y = 87

2. Add the two equations to eliminate y. This gives:

29x = 87

3. Divide both sides by 29 to solve for x. This gives:

x = 3

4. Substitute x = 3 into one of the original equations to solve for y. For example, using the first equation, we get:

5(3) - 3y = 0 15 - 3y = 0 -3y = -15 y = 5

5. Check the solution by plugging in x = 3 and y = 5 into the other original equation. We get:

3(3) + 4(5) = 29 9 + 20 = 29 29 = 29

The solution is correct. Therefore, the system of equations has a unique solution: (x, y) = (3, 5).

If you want to learn more about systems of linear equations, you can watch some videos , , or read some articles , , , .

: Systems of equations | Algebra 1 | Math | Khan Academy : How do we solve a system of linear equations using any method : Linear Equations - Algebra : Solving System of Linear Equations by Substitution Method | Solution of System of Equations : Solving systems of linear equations | Lesson - Khan Academy : Systems of equations | Algebra 1 | Math | Khan Academy : How to Solve a System of Linear Equations - ThoughtCo : 5.3: Solve Systems of Equations by Eliminationhow to solve a system of linear equations