Question

X^4-3x^2-4=0 помогите пожалуйста. Срочно

Answer 1

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Answer 2

Solving the Equation X^4-3x^2-4=0

To solve the equation X^4-3x^2-4=0, we can use the quadratic formula or factorization to find the values of x that satisfy the equation.

Using the quadratic formula, we can find the roots of the equation by considering it as a quadratic in terms of x^2. The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

Where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.

Applying the Quadratic Formula

For the equation X^4-3x^2-4=0, we can substitute a=1, b=-3, and c=-4 into the quadratic formula to find the roots of the equation.

x^2 = (-(-3) ± √((-3)^2 - 4*1*(-4))) / (2*1)

x^2 = (3 ± √(9 + 16)) / 2

x^2 = (3 ± √25) / 2

x^2 = (3 ± 5) / 2

So, the solutions for x^2 are:

x^2 = (3 + 5) / 2 = 8 / 2 = 4

x^2 = (3 - 5) / 2 = -2 / 2 = -1

Finding the Values of x

To find the values of x, we take the square root of x^2:

x1 = √4 = 2

x2 = √(-1) is not a real number

Therefore, the solutions for the equation X^4-3x^2-4=0 are:

x1 = 2

x2 = -2

These are the real roots of the given equation.

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