Question

Из поселка в город одновременно выехали мотоциклист со скорость 40 км/ч и велосипедист со скоростью 10 км/ч. Определите какое время затратил на путь велосипедист если известно что он прибыл в город на 1,5 часа позже мотоциклиста

Answer 1

Пусть мотоциклист затратил на весь путь х часов, тогда велосипедист х+1,5 часа. При этом они проехали одинаковый путь. Составим уравнение:
40х = 10(х+1,5)
40х=10х+15
40х-10х=15
30х=15
х=0,5
Мотоциклист затратил 0,5 часа, велосипедист затратил 0,5+1,5=2 часа
Ответ: 2 часа.  

Answer 2

Calculating the Time Taken by the Cyclist to Reach the City

To calculate the time taken by the cyclist to reach the city, we can use the formula: time = distance / speed

Given that the motorcyclist traveled at a speed of 40 km/h and the cyclist at a speed of 10 km/h, and the cyclist arrived in the city 1.5 hours after the motorcyclist, we can calculate the time taken by the cyclist.

The distance traveled by both the motorcyclist and the cyclist is the same, as they started from the same place and arrived at the same destination.

Using the formula, we can calculate the time taken by the cyclist.

time taken by the cyclist = distance / speed of the cyclist

time taken by the motorcyclist = distance / speed of the motorcyclist

Given that the time taken by the cyclist is 1.5 hours more than the time taken by the motorcyclist, we can set up the following equation:

time taken by the cyclist = time taken by the motorcyclist + 1.5

Now, let's calculate the time taken by the cyclist.

Using the given speeds: - Speed of the motorcyclist = 40 km/h - Speed of the cyclist = 10 km/h - Time taken by the motorcyclist = t (in hours)

We can use the equation: time taken by the cyclist = time taken by the motorcyclist + 1.5

Substituting the values: distance / 10 = distance / 40 + 1.5

Solving for the time taken by the cyclist: distance / 10 - distance / 40 = 1.5

This equation can be solved to find the time taken by the cyclist.

The time taken by the cyclist to reach the city can be calculated using the above method.