Question

Один арбуз на 2 кг легче ,чем другой,и в 5 раз легче,чем третий.Первый и третий арбуз вместе в 3 раза тяжелее,чем второй .Найти массу каждого арбуза.

Answer 1

Пусть 1 арбуз будет -кг, тогда 2-ой арбуз х+2, а 3-ий 5х.
Составляем уравнение:
х+5х=3(х+2)
6х=3х+6
6х-3х=6
3х=6
х=6/3
х=2 кг 1 арбуз
2+2=4 кг 2-ой арбуз
5*2=10кг 3-ий арбуз
Ответ: масса 1-го арбуза 2кг, масса 2-го арбуза 4кг, масса 3-го арбуза 10кг.

Answer 2

Problem Analysis

We are given three watermelons, and we need to find the mass of each watermelon. The information provided is as follows: - One watermelon is 2 kg lighter than the other. - One watermelon is 5 times lighter than the third watermelon. - The combined mass of the first and third watermelons is 3 times heavier than the second watermelon.

Let's assume the masses of the three watermelons are A, B, and C, respectively.

Solution

To solve this problem, we can set up a system of equations based on the given information and solve for the unknowns.

1. One watermelon is 2 kg lighter than the other: - A = B + 2 2. One watermelon is 5 times lighter than the third watermelon: - B = C/5 3. The combined mass of the first and third watermelons is 3 times heavier than the second watermelon: - A + C = 3B Now, we can substitute the values from equations 1 and 2 into equation 3 to solve for the masses of the watermelons.

Substituting B = C/5 from equation 2 into equation 3: A + C = 3(C/5) 5A + 5C = 3C 5A = -2C A = -2C/5

Now, we can substitute A = -2C/5 into equation 1 to solve for B: -2C/5 = B + 2 B = -2C/5 - 2

We have expressions for A, B, and C in terms of C. Let's solve for C first.

Substituting B = -2C/5 - 2 into equation 2: -2C/5 - 2 = C/5 -2C - 10 = C -3C = 10 C = -10/3

Since the mass of a watermelon cannot be negative, we discard this solution.

Therefore, there is no valid solution for the masses of the watermelons based on the given information.

Conclusion

Based on the given information, we cannot determine the mass of each watermelon. The problem does not have a valid solution.