Question

Расстояние АВ, равное 110 км, турист прошёл за три дня. За второй день пути он прошёл на 5 км больше, чем за первый, а за третий - 3/7 расстояния, пройденного за два первых дня. Сколько километров проходил турист за каждый день пути?Помогите пожалуйста))

Answer 1

110 км  -  всего за 3 дня
х км  -  за I день
х + 5 (км)  -  за II день
(х + х + 5) * 3/7  -  за III день
? км  -  за каждый день

1) х + (х + 5) + (х + х + 5) * 3/7 = 110
    2х + 5 + (2х + 5) * 3/7 = 110
    2х + 5 + 6/7x + 15/7 = 110
    2 6/7x + 5 + 2  1/7 = 110
    2 6/7x + 7  1/7 = 110
    2 6/7x = 110 - 7  1/7
    2 6/7x = 102  6/7
    20/7x = 720/7
    x = 720/7 * 7/20
    x = 36 км - в I день
2) 36 + 5 = 41 км - во II день
3) (36 + 41) * 3/7 = 77 * 3/7 = 33 км - в III день.

Answer 2

Problem Analysis

We are given that a tourist walked a distance of 110 km over three days. On the second day, the tourist walked 5 km more than on the first day, and on the third day, the tourist walked 3/7 of the distance covered in the first two days. We need to determine the distance walked by the tourist each day.

Solution

Let's assume that the distance walked on the first day is x km.

According to the given information, the distance walked on the second day is 5 km more than the distance walked on the first day. Therefore, the distance walked on the second day is x + 5 km.

The distance walked on the third day is 3/7 of the total distance covered in the first two days. The total distance covered in the first two days is x + (x + 5) km. Therefore, the distance walked on the third day is (3/7) * (2x + 5) km.

We know that the total distance covered over the three days is 110 km. Therefore, we can write the equation:

x + (x + 5) + (3/7) * (2x + 5) = 110

Now, let's solve this equation to find the value of x.

Calculation

x + (x + 5) + (3/7) * (2x + 5) = 110

Simplifying the equation:

2x + 5 + (6/7)x + (15/7) = 110

Combining like terms:

(20/7)x + 20/7 = 110

Subtracting 20/7 from both sides:

(20/7)x = 110 - 20/7

Simplifying:

(20/7)x = 770/7 - 20/7

(20/7)x = 750/7

Dividing both sides by 20/7:

x = (750/7) / (20/7)

Simplifying:

x = 750/20

x = 37.5

Therefore, the distance walked on the first day is 37.5 km.

The distance walked on the second day is 37.5 + 5 = 42.5 km.

The distance walked on the third day is (3/7) * (2 * 37.5 + 5) = 30 km.

Answer

The tourist walked 37.5 km on the first day, 42.5 km on the second day, and 30 km on the third day.