Question

. 1)X+3 4 ___ = _ 12 3 2)3x+16=9-10x 3)3(1-x)+5(x+2)=1-4x 4)10x+3(72x)=12+2 5)0,6x+100=0,9x-31

Answer 1

1-?
2-)3х+16-9+10х=0
13х+7=0
х= -7/13
3-)3-3х+5х+10-1+4х=0
6х+12=0
х= -2
4-)10х+216х-12-2=0
226х-14=0
х= 14/226= 7/113
5-)0,6х+100-0,9х+31=0
-0.3х+131=0
х= -131/0.3

Answer 2

1) X + 3 + 4 + ___ = _ + 12 + 3 To solve for the missing number, we can combine like terms on both sides of the equation: X + 7 + ___ = _ + 15

We can see that the missing number is 8, so the complete equation is: X + 7 + 8 = X + 15

2) 3x + 16 = 9 - 10x To solve for x, we can combine like terms and isolate x on one side of the equation: 3x + 10x = 9 - 16 13x = -7 x = -7/13

3) 3(1-x) + 5(x+2) = 1 - 4x First, distribute the numbers inside the parentheses: 3 - 3x + 5x + 10 = 1 - 4x Combine like terms: 2x + 13 = 1 - 4x Isolate x on one side of the equation: 2x + 4x = 1 - 13 6x = -12 x = -2

4) 10x + 3(72x) = 12 + 2 First, simplify the equation by multiplying the numbers inside the parentheses: 10x + 216x = 14 Combine like terms: 226x = 14 Isolate x on one side of the equation: x = 14/226 x = 7/113

5) 0.6x + 100 = 0.9x - 31 To solve for x, first, we can subtract 0.6x from both sides of the equation: 100 = 0.3x - 31 Then, add 31 to both sides: 131 = 0.3x Finally, divide by 0.3 to solve for x: x = 131/0.3 x = 437.33