Question

Х^2=2х+8 помогите пожалуйста

Answer 1

X^2-2x-8=0
D=-2^2-4*-8=4+32=36
x1=2+6/2=8/2=4
x2=2-6/2=-4/2=-2

Answer 2

X^2-2x-8=0
D=-2^2-4*(-8)=36
x1=2+√36/2=4
x2=2-√36/2=-2

Answer 3

Solving the Equation x^2 = 2x + 8

To solve the equation x^2 = 2x + 8, we can rearrange it into a quadratic equation and then solve for the values of x.

First, let's rearrange the equation to form a quadratic equation in standard form: x^2 - 2x - 8 = 0

Now, we can use the quadratic formula to solve for the values of x: x = (-b ± √(b^2 - 4ac)) / (2a)

Where a, b, and c are the coefficients of the quadratic equation.

Applying the Quadratic Formula

Using the quadratic formula, we can find the values of x by substituting the coefficients of the quadratic equation: a = 1, b = -2, c = -8

Now, let's calculate the values of x using the quadratic formula: x = (-(-2) ± √((-2)^2 - 4*1*(-8))) / (2*1)

This simplifies to: x = (2 ± √(4 + 32)) / 2 x = (2 ± √36) / 2 x = (2 ± 6) / 2

So, the solutions for x are: x = (2 + 6) / 2 = 8 / 2 = 4 x = (2 - 6) / 2 = -4 / 2 = -2

Therefore, the solutions for the equation x^2 = 2x + 8 are: x = 4 and x = -2.

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