Question

В 10 ящиках было по одинаковому количеству яблок. Когда из первого ящика взяли несколько яблок, из второго на одно яблоко больше, из третьего на два яблока больше и так далее, то в последнем ящике 21 яблоко. Сколько яблок осталось в первом ящике?

Answer 1

31 яблок в каждом ящике. А значит в 1 ящике тоже 31 яблок. Теперь мы вычетаем то число сколько забрали и получаем 30. Ответ: 30 яблок а первом осталось.
x-10=21
x=21+10
x=31 - яблок в каждом ящике по условию.
31-1=30 - в первом ящике осталось.

Answer 2

Problem Analysis

We have 10 boxes, each containing the same number of apples. When we take some apples from the first box, the second box has one more apple than the first box, the third box has two more apples than the first box, and so on. The last box contains 21 apples. We need to determine how many apples are left in the first box.

Solution

Let's assume that the number of apples in each box is x.

According to the given information, the number of apples in the second box is one more than the number of apples in the first box. So, the number of apples in the second box is x + 1.

Similarly, the number of apples in the third box is two more than the number of apples in the first box. So, the number of apples in the third box is x + 2.

We can continue this pattern for all the boxes until the last box, which contains 21 apples.

To find the number of apples in the first box, we can use the following equation:

x + (x + 1) + (x + 2) + ... + (x + 9) = 21

Simplifying the equation, we get:

10x + 45 = 21

Solving for x, we find:

x = -2.4

However, since we are dealing with apples, the number of apples cannot be negative or fractional. Therefore, there is no valid solution to this problem.

Conclusion

Based on the given information, there is no valid solution for the number of apples left in the first box.