Question

Решите плиз!((a+2b)/(a+b)^2-((a-4b)/(a^2-b^2)) : ((b^2+2ab)/((a+b)^2))

Answer 1

надеюсь будет понятно..

Answer 2

I can help you with math problems. Here is the solution to your question:

To simplify the expression, we need to factor the denominators and cancel out the common terms. We get:

$$\frac{a+2b}{(a+b)^2}-\frac{a-4b}{(a-b)(a+b)}+\frac{b^2+2ab}{(a+b)^2}$$

$$=\frac{(a+2b)(a-b)}{(a+b)^2(a-b)}-\frac{(a-4b)(a+b)}{(a-b)(a+b)^2}+\frac{(b^2+2ab)(a-b)}{(a+b)^2(a-b)}$$

$$=\frac{a^2-ab+2ab-2b^2-a^2-4ab+4b^2+b^2+2ab-2ab^2}{(a+b)^2(a-b)}$$

$$=\frac{-ab-2ab^2}{(a+b)^2(a-b)}$$

$$=-\frac{ab(1+2b)}{(a+b)^2(a-b)}$$

This is the final answer. I hope this helps.Ответь+подробно.+Решите+плиз!((a+2b)/(a+b)^2-((a-4b)/(a^2-b^2))+:+((b^2+2ab)/((a+b)^2))