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СРОЧНО ПОМОГИТЕ СИСТЕМА УРОВНЕНИЙ 6 КЛАСС!!!!!!!!!!!!!{х+2у=6{2х+4у=12​ Посмотреть ответы Участник Знаний Участник Знаний Умножим первое уравнение на минус два и сложим со вторым, получим-2х-4у=-122х+4у=12​0=0, решений бесчисленное множество, т.к. прямые, которые задаются уравнениями, будут сливаться. у=3-х/2, например, х=0; у=3, т.е. решение (0;3), если х=3, то у=3-1=2, решение (2;2) и т.д.Т.к. прямая сливается с другой прямой, то достаточно построить прямуюх+2у=6, и любая точка на ней будет решением. Выражаем х через у, получаемх=-2у+6для построения прямой нужно задать две точки, если у=2, то х=-2*2+6=2Если же у=3, то х=-2*3+6=0имеем таблицу___х______2_______0_      у______2_______3__у=3-0.5х- уравнение прямой. график ниже. спасибо,и извиняюсь я затупила ":> решите графическим способом отмечу как лучший ответ aiazhanumar aiazhanumar {x+2y=6{2x+4y=12{x=6-2y{2×(6-2y)+4y=1212-4y+4y=12 Новые вопросы в Алгебра Помогите пожалуйста даю 20 баллов На картинці Рєпіна "козаки пишуть листа турецькому султану" 3/8 козаків з "оселедцями", 2/3 решти- у шапках і 5 козаків зі зброєю. Скільки козаків зоб … ражено на картині?​ Помогите пожалуйста!!!!!!!! Упростите выражение ​ упростить выражение: (1/x-y - 1/x+y) : 2/3x-3y Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Answer 1

Ваши уравнения:

1) x + 2y = 6 2) 2x + 4y = 12

Мы можем решить эти уравнения, используя метод подстановки или умножение на минус два в первом уравнении и сложение с вторым уравнением.

Метод подстановки:

1) Заменим x из второго уравнения на выражение из первого уравнения:

x = 6 - 2y

Подставим это в второе уравнение:

2x + 4y = 12 => (6 - 2y) + 4y = 12 => 6 = 12

Ошибка в условии, так как 6 не равно 12. Возможно, есть ошибка в условии задачи.

Метод умножения на минус два и сложения:

1) Умножим первое уравнение на -2 и сложим с вторым уравнением:

-2x - 4y + 2x + 4y = -12 + 12 => 0 = 0

Это означает, что любое значение x и y удовлетворяет системе уравнений.

Построим график системы уравнений:

1) Выразим x через y, подставив y из первого уравнения в первое уравнение:

x = 6 - 2y

Это уравнение представляет собой прямую, которая проходит через точку (3;2) и (0;3).

Таким образом, любая точка на этой прямой будет решением системы уравнений.