Question

1//х+1 + 2//х-1 = 4//х-3

Answer 1

Если я правильно поняла условие, то смотри ответ

Answer 2

To solve the equation:

1/(x + 1) + 2/(x - 1) = 4/(x - 3)

You can start by finding a common denominator and then combining the fractions. The common denominator in this case is (x + 1)(x - 1)(x - 3). So, you need to rewrite each fraction with this common denominator:

[(x - 1)(x - 3) + 2(x + 1)(x - 3) = 4(x + 1)(x - 1)] / [(x + 1)(x - 1)(x - 3)]

Now, you can simplify the equation:

(x - 1)(x - 3) + 2(x + 1)(x - 3) = 4(x + 1)(x - 1)

Expand the terms:

(x^2 - 4x + 3) + (2x^2 - 4x - 6) = 4(x^2 - 1)

Now, combine like terms:

3x^2 - 8x - 3 = 4x^2 - 4

Next, move all terms to one side of the equation:

3x^2 - 8x - 3 - 4x^2 + 4 = 0

Simplify further:

-x^2 - 8x + 1 = 0

Now, you have a quadratic equation. To solve for x, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

In this case, a = -1, b = -8, and c = 1. Plug these values into the formula:

x = (-(-8) ± √((-8)² - 4(-1)(1))) / (2(-1))

x = (8 ± √(64 + 4)) / (-2)

x = (8 ± √68) / (-2)

Now, you can simplify this further:

x = (-4 ± √68) / (-2)

x = 2 ± √17

So, the solutions for the equation are:

x = 2 + √17 x = 2 - √17